A student taking two courses history and math. The probability the student will pass the history course is .60

A student taking two courses history and math. The probability the student will pass the history course is .60,k and the probability of passing the math course is .70. The probability of passing both is .50. What is the probability of passing at least one?

A student taking two courses history and math. The probability the student will pass the history course is .60
0.6+0.7-0.5 = 0.8
Reply:For any two events A and B


P(A and B) = P(A) + P(B) - P(A or B)


P(A or B) = P(A) + P(B) - P(A and B)








Let H be the event of passing the history class


Let M be the event of passing the math class





P(H or M) = P(H) + P(M) - P(H and M)


P(H or M) = 0.6 + 0.7 - 0.5


P(H or M) = 0.8





The probability of passing history or math (and this includes the intersection of passing both) is 80%